Question

17. The base of a parallelogram is three fourth of its height. If the area is 243sqcm, find the
base and height​

Answer 1

Step-by-step explanation:

$let \: the \: base \: of \: the \: parallelogram \: be \: x \: and \: height \: be \: h \\ according \: to \: question \\ x = \frac{3h}{4} - - (i) \\ </p><p>area of parallelogram = 243 {cm}^{2} \\ base × height = 243 \\ x × h = 243 \\ \frac{3h}{4} × h =243 \\ \frac{3h^2}{4} = 243 \\ h^2 = \frac{243 \times 4}{3} \\ h^2 = 324 \\ h = \sqrt{324} \\ h = 18cm \\ put \: the \: value \: of \: h \: in \: equation \: (i) : \\ x = \frac{3 \times 18}{4} \\ = \frac{54}{4} \\ = 13.5cm$

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