Question

17.
The brakes of an automobile can produce a constant deceleration 2m/s2. After
application of brakes the vehicle comes to rest in 9s. Find the stopping distance.
A) 27m
B) 45m
C) 63m
D) 81m
nbile can produce a constant deceleration 3m/s2. Find the
it comes to rest in 6s.​

Answer 1

Answer:

Explanation:

Accerleration: a=−6 m/s  

2

 

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+  

2

1

​  

at  

2

 

s=12×2+  

2

1

​  

×(−6)×4

⇒s=12 m