17. The diagram shows a Simple pendulum. Rahul was doing the experiment in the Physics lab. He counted 10 oscillations in 20 seconds for first time.
a. What is the time period and frequency of its oscillation?
b. When second time he did the experiment, he observed 10 oscillations in 25 seconds. What is the new time period and frequency?
c. What will be his final result?
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a)time period=total time/total oscillations
=20/10=2s
frequency=1/t = 1/2 Hz
b) t= 25/10 =2.5s or 5/2 s
f= 2/5 Hz
c) no : of oscillations= 10+10=20
total time =20+25=45s
T= 45/20 =2.25s or 9/4s
F= 4/9 Hz
=20/10=2s
frequency=1/t = 1/2 Hz
b) t= 25/10 =2.5s or 5/2 s
f= 2/5 Hz
c) no : of oscillations= 10+10=20
total time =20+25=45s
T= 45/20 =2.25s or 9/4s
F= 4/9 Hz
aleenbarbie:
thanks a lot lekshmi
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