Math, asked by exclusiverandomoffic, 4 months ago

17) The equation of the plane passing through the points (1,-1, 1), (3, 2, 4) and parallel to Y-axis
is :
A) 3x+2z-1=0
B) 3x -2z=1
C) 3x+2z+1 =0
D) 3x+2z =2​

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Answers

Answered by honey1165
0

Answer:

Let the equation of plane be a(x−x1)+b(y−y1)+c(z−z1)=0

If passes through (2,2,1)

∴ Equation is a(x−2)+b(y−2)+c(z−1)=0

Vector normal to plane is the cross product of vectors

(2i^−j^+2k) and (i^+j^−k^)

n=⎣⎢⎢⎡i^31j^−11k^2−1⎦⎥⎥⎤

=i^(1−2)−j^(−3−2)+k^(3+1)

=−i^+5j^+4k^

∴ Equation of plane is 

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