Question

17. The following table gives you the distribution of marks secured by some students in an
examination.
0-20
21-30
31-40
41-50
51-60
61-70
71-80
no of students:
42
38
120
84
48
36
32
Find (i) Median marks
(ii) the percentage of failures, if the minimum for a pass is 35 marks.
(Ans. 40.5 and 30.5)​

Answer 1

Given :  distribution of marks secured by some students in a certain examination :

To Find : Median marks.

Solution:

Marks     f              cf

0-20      42           42  

21-30     38           80

31-40     120         200

41-50     84          284

51-60     48          332

61-70     36           368

71-80     31            399

399/2 = 199.5

Median =  30.5  +  10 * ( 199.5 - 80)/120

= 30.5  +  9.958

= 40.458

= 40.46

Median Marks   =  40.46

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Answer 2

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40.46