Question

17. The hands of a clock are 10 cm and 7 cm respectively.
the difference between the distance traversed by their extremities in 3 days 5 hours is (M.A.T., 2006)
The difference bet
(a) 4552.67 cm
(c) 4557.67 cm
(b) 4555.67 cm
(d) 4559.67 cm
​

Answer 1

Answer:

The hands of a clock are 10 cm and 7 cm respectively.

the difference between the distance traversed by their extremities in 3 days 5 hours is (c) 4557.67 cm

Step-by-step explanation:

3 days 5 hours = 3 * 24 + 5 = 77 hr

Minute Hand = 10 cm , Hour hand = 7 cm

Circumference of circle = 2πR   π = 22/7

Distance traveled by Minute hand in 1 hrs =  2 * (22/7) * 10

Distance traveled by Hour hand in 77 hrs =  2 * (22/7) * 10* 77 = 4840 cm

Distance traveled by Hour hand in 12 hrs =  2 * (22/7) * 7

Distance traveled by Hour hand in 1 hrs =  44 /12

Distance traveled by Hour hand in 77 hrs =  (44/12 )* 77 = 282.33 cm

Difference = 4840 - 282.33 = 4557.67 cm

option (c) 4557.67 cm is correct