Math, asked by NiaGue, 4 months ago


17. The number of nine non-zero digits such that all the digits in the first four places are less than the digit in the middle and all the digits in the last four places are greater than that in the middle, is
(a) 48
(b) 7560
(c) 10080
(d) 576​

Answers

Answered by muskan474941
1

Answer:

10080 is the answer.......

Answered by s1685shashank5406
0

Answer:

123456789

Step-by-step explanation:

1234 before 5 middle digit and smaller than 5

6789 next to 5 and greater than 5

all the options are wrong if it is a 9 digit no.

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