Question

17) The photoelectric cut off voltage in an experiment was found to be 1.5v the
work function for the material used in the experiment was 4.2ev the maximum
K.E of photoelectron that was emitted was
a) 1.5 ev
b) 2 7 ev
C) 4.2 ev
d) 5.7 ev​

Answer 1

please correct the question !!

as of now if i take 1.5 V to be cut off . thats the voltage in which we will observe max KE

KE = eV = 1.5eV