Question

17.
The series limit for the Balmer series of
ionised helium is [RH= 1.09 x 10^7m^-1]
(A) 264 nm (B) infinity
(C) 367 nm (D) 122 nm​

Answer 1

Answer:

367mm hope it will help you

Answer 2

Answer:

367 nm.

Explanation:

Since, we know for the Balmer series the n2 is 2 and the n1 is infinity which is the upper orbital limit is infinity. Since, we know that the wavelength of the series can be calculated using the formulae of 1/λ = Rh(1/n2^2 - 1/n1^2) here Rh is the Rydberg's constant which is given as 1.09 x 10^7m^-1 and the λ is the wavelength of the required Balmer series.

So, 1/λ = Rh(1/n2^2 - 1/n1^2) now putting the values of n2 as 2 and n1 as infinity we will get 1/λ = 1.09 x 10^7(1/4 - 0) which on solving we will get the value of λ as 367 nm.