Question

17. The solution of (a ^ 2)/x - (b ^ 2)/y = 0 and (a ^ 2 * b)/x + (b ^ 2 * a)/y = a + b where x, y ne0 is a. x = - a ^ 2 and y = - b ^ 2 b. x = a ^ 2 and y = - b ^ 2 c. x = a ^ 2 and y = b ^ 2 d. x = - a ^ 2 and y = b ^ 2​

Answer 1

Answer:

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