Question

17. The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio
7:8:9. Their present ages are
(a) (45, 50, 55)
(b) (40, 60, 50) (c)(35, 45, 70) (d) none of these​

Answer 1

GIVEN

The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio 7:8:9.

TO FIND

Their Present ages

SOLUTION

Let the ages of the person 10 yrs ago be 7x, 8x, 9x according to the question.

Present ages will be 7x + 10, 8x+10 and 9x + 10

Now according to the Question,

(7x + 10) + (8x + 10) + (9x + 10) = 150

=> 24x + 30 = 150

=> 24x = 150 - 30

=> 24x = 120

=> x = 5

Therefore Present ages are

7x + 10 = 45yrs

8x+10 = 50yrs

9x + 10 = 55yrs

Hence their Present Ages are 45,50 and 55yrs. (ANS)

Answer 2

Answer:

Opt.(a) 45,50,55

Step-by-step explanation:

Given that, 10 years ago, their ages were in ratio 7 : 8 : 9.

Thus, let their ages 10 years ago be 7x, 8x, 9x respectively.

Their present ages = 7x + 10, 8x + 10, 9x + 10 respectively.

Given that, Sum of ages = 150

» 7x + 10 + 8x + 10 + 9x + 10 = 150

» 24x + 30 = 150

» 24x = 120

• » x = 5

Thus,

Their present ages :

7x + 10 = 7(5) + 10 = 45

8x + 10 = 8(5) + 10 = 50

9x + 10 = 9(5) + 10 = 55

Thus, Their present ages are 45,50,55 years respectively.