Question

17. The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio
7:8:9. Their present ages are
(a) (45,50,55) (b) (40,60,50) (©) (35, 45, 70) (d) none of these

Answer 1

Answer:

45,50,55

Step-by-step explanation:

sum=150

ratio of ages 10 yrs ago=7:8:9

sum-30 = sum of ages 10 yrs ago

150-30=120

7x+8x+9x=120

24x=120

x=5

ages 10 yrs ago=35,40,45

present ages =45,50,55

Answer 2

Answer:

none of these

Step-by-step explanation:

Let the age of one person be x second be y and third be z

x+y+z=150

before 10 years

x-10+y-10+z-10=150

x+y+z-30=150

x+y+z=120

but the ages before ten years are in ratio 7:8:9

so let there ages be 7x,8x,9x

7x+8x+9x=120

24x=120

x= 5

after ten years x= 15

so the answer in this mcq is none of these