Question

17. The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio
7:8:9. Their present ages are
(a) (45, 50, 55)
(b) (40, 60,50) (c)(35, 45,70) (d) none of these​

Answer 1

Answer:

Jai Hind

Step-by-step explanation:

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Brainliest.....

Answer 2

Answer:

option a

Step by step explanation:

Let x be the age of 1st person,y be the age of 2nd person and z be the age of 3rd person.

$x + y + z = 150$

10 years age their ages were,

$150 - (10 + 10 + 10) = 120$

Their ages are in the ratio 7:8:9 and addition of their ages are 120

multiply these ratio with 5 we get,

35,40,45

35+40+45=120

it satisfies the 2nd condition

so their present ages of

1st person. =35+10=40

2nd person = 40 +10=50

3rd person = 45+10=55

I hope this will help u