Question

17. The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio
7:8:9. Their present ages are
(a) (45, 50, 55)
(b) (40,60, 50)
(c) (35, 45, 70)
(d) none of these​

Answer 1

Answer:

Step-by-step explanation:

the sum of the ages of three persons x,y,z=150

x+y=150-z

10 years ago their ages were in the ratio = 7:8:9

(x-10)(y-10)(z-10)=x+y+z-30=150-30=120

7a+8a+9a=120

24a=120

a=5

their ages are

7(5),8(5),9(5)=35,40,45(their ages 10 yrs ago)

now at present their ages are =45,50,55