17. The tens digit of a certain two-digit number exceeds the units digit by 4 and is 1 less than
twice the units digit. Find the digit number.
18. The sum of the digits of a certain two-digit number is 10. If the digits are reversed, a new
number is formed which is one less than twice the original number. Find the original number
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Answer:
Q-17=95
Q-18=37 is the original no
Step-by-step explanation:
Q-17 Let x=the ten digit
Let y=the unit digit
x=y+4 (ten digit is 4 greater than the unit digit)
x=2y-1 (ten digit is 1 less than twice the unit digit)
subtract 1st equation from 2nd
0=y-5 or y=5 x=5+4=9
the two digit number is 95
Q-18 The statement "If the digits are reversed, a new number is formed which is 1 less than twice the original number." is expressed by the equation 2(10x + y) - 1 = 10y + x. If you substitute 10 - x for y in this equation and solve, you get x = 3. Thus y = 7, so the original number is 37
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