Math, asked by ammu717, 9 months ago

17. The vertices of a AABC are A(2, -11), B12, 13) and C(-12, 1).
Find the equations of its sides,
13 4 11 24
Hint. The slope of AB =
which is not defined.
2-2 0
- AB is parallel to y-axis . Its equation is x =
Also, it passes through (2, -11). So, a = 2. Hence, = 2.)

Answers

Answered by ankita5791
0

Answer:

sorry I didn't now ......

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