Question

17. Three wires of length 403 metres, 434 metres, 465 metres have to be divided into pieces of
same length. What is the greatest possible length of each piece ?​

Answer 1

Answer:

Find the HCF of the three numbers.

HCF of 403,434,465 = 31.

Hence the greatest possible length of each piece is 31 m.

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Answer 2

Answer:

31 m

Step-by-step explanation:

The maximum capacity of container = H.C.F. of (403, 434, 465)

Factors of 403 = 13 x 31

Factors of 434 = 2 x 7 x 31

Factors of 465 = 3 x 5 x 31

H.C.F = 31

Therefore, 31 m of container is required to measure the quantity.