Question

17. Two equal sides of a triangle are each 5 metres less than twice the third side. If the perimeter a
the triangle is 55 meters, find the lengths of its sides.
angles.​

Answer 1

Answer:

let the third side x meters Then according to the question,other two sides are (2x−5) meters each.

Then,2x−5+2x−5+x=55

5x−10=55

5x=65

x=13m

Thus other two sides are 2×13−5=21m each.

Step-by-step explanation:

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Answer 2

Answer:-

Let third side be x metres

ATQ, the other two sides are (2x -5) metres each

Then,( 2x-5)+ (2x-5) + x= 55

5x- 10= 55

5x=65

x= 13m

therefore, other two sides are

(2×13-5)= 21 m each..

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