17. Two taps can fill a tank in 10 hours and 12 hours respectively. An outlet pipe takes60 hours to empty the tank. If the 2 taps andthe outlet pipe are all opened together, how long will it take for the tank to be filled?
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Answer:
Consider x, y and z are the velocity in three different pipes and v as volume of he tank. Then,
10x = 12y = 20z = v
Hence
y = x/2 x and z = 5x/6
Considering all the three pipes are working,
No of hours * (x+y-z) = v
No of hours *(x + 1/2x + 5/6x) = v
No of hours*4x/3 = v
With velocity of x, the tank is filled in 10 hrs.
Then with velocity of 4x/3, time taken will be
3*10/4 = 7.5 hrs
When all the three pipes are working simultaneously, time taken to fill the tank is 7.5 hours
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