17) Urea is a very important nitrogenous fertilizer. Its formula is CON.H.Calculate the percentage of carbon in urea
(C = 12,0 = 16, N = 14 and H= 1)
Answers
Answered by
25
Explanation:
ElementNo of atomsAtomic massTotalH21428C11212H414O11616[12+16+28+4=60]
Hence, relative molecular mass of urea =60
Percentage of carbon = weight of carbon / Total weight of urea ×100
=12/60×100
=20 or 20%
Answered by
3
Explanation:
Element No of atoms Atomic mass Total
H 2 14 28
C 1 12 12
H 4 1 4
O 1 16 16
[12+16+28+4=60]
Hence, relative molecular mass of urea =60
Percentage of carbon = weight of carbon / Total weight of urea ×100
=12/60×100
=20 or 20%
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