17.
What is the principal amount on which the difference between the compound interest
and simple interest is Rs. 40, after two years at the rate of annual interest 5%?
Answers
Answered by
1
Answer:
Step-by-step explanation:
Answer:p = Principal; n= Years; r= Rate of Interest
n here is 2 years and r is 20% per annum
Simple Interest (S) = (p*n*r)/100 = (p*2*20)/100 = 40p/100 = 0.4p
Compound Interest (C) = [p*(1+(r/ 100)^n)] -p = [p*(1+0.2)^2]-p = 1.44p - p = 0.44p
0.44p = 0.4p+96 ===> 0.04p = 96.00 ===> p = 96.00/0.04 = 2400
Answered by
0
Difference = P(R)²/(100)²
Where P = principal amount, R = rate of interest
If the difference between compound and simple interest is of three years than,
Difference = 3 x P(R)²/(100)² + P (R/100)³.
Here also, P = principal amount, R = rate of interest
Step-by-step explanation:
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