Math, asked by aashish8032, 1 month ago

17.
What is the principal amount on which the difference between the compound interest
and simple interest is Rs. 40, after two years at the rate of annual interest 5%?​

Answers

Answered by shivasinghmohan629
1

Answer:

Step-by-step explanation:

Answer:p = Principal; n= Years; r= Rate of Interest

n here is 2 years and r is 20% per annum

Simple Interest (S) = (p*n*r)/100 = (p*2*20)/100 = 40p/100 = 0.4p

Compound Interest (C) = [p*(1+(r/ 100)^n)] -p = [p*(1+0.2)^2]-p = 1.44p - p = 0.44p

0.44p = 0.4p+96 ===> 0.04p = 96.00 ===> p = 96.00/0.04 = 2400

Answered by 755884
0

Difference = P(R)²/(100)²

Where P = principal amount, R = rate of interest

If the difference between compound and simple interest is of three years than,

Difference = 3 x P(R)²/(100)² + P (R/100)³.

Here also, P = principal amount, R = rate of interest

Step-by-step explanation:

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