Question

17.What is the value of m, if x²+ mx – 28 = ( x – 7 ) ( x + 4 ) *​

Answer 1

Answer:

3

Step-by-step explanation:

x=7 and -4

x²+mx+-28=0

0=7²+m[7]-28

0=49+7m-28

0=21+7m....... Eq1

x²+mx-28=0

0=[-4]²+m[-4]-28

0=16-4m-28

0= -12-4m.............Eq2

Eq1=Eq2

21+7m= -12-4m

21+12=-4m-7m

33= -11m

33/-11=m

m= -3

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