Question

17. Work done in expanding 10 moles of an ideal
gas,
isothermally and reversibly from a pressure of 5 atm
1 atm at 300 K is
(a) -9.65 x 103 J
(b) - 40.15 x 103J
(c) - 9.65 x 102 J
(d) - 40.15 x 102J​

Answer 1

Answer:

d) -40.15× 102J

Explanation:

w

exp

=−2.303nRTlog

P

2

P

1

=−2.303(10 mol)×(8.314 JK

−1

mol

−1

(300 K)log

1

5

=−40.15×10

3

J

If M is the mass that can be lifted by this work, through a height of 1 metre, then

work done =Mgh

40.15×10

3

J=M×9.81 ms

−2

×1 m

or M=

9.18 ms

−2

×1m

40.15×10

3

kgm

2

s

−2

(J=kg m

2

s

−2

)

=4092.76 kg.