Question

17] Write a quadratic polynomial, its zeroes are 9 and -5.​

Answer 1

Answer:

$\huge\orange{\boxed{\sf AnSwEr}}$

Given Zeroes :

9,-5

let these be

$\alpha \: and \: \beta$

we know that a Quadratic Equation is of form

$\huge\green{\boxed{\sf x²+(sum\: of \:roots)+ product\: of \:roots )}}$

So put the values

x²+(9-5) x+9×-5

$\huge\red{\boxed{\sf x²+4x-45}}$ is required Equation

Answer 2

Answer:

$x^{2} -4x-45$

Step-by-step explanation:

so the zeroes are $\alpha =9$, $\beta =-5$

so sum of zeroes,

$\alpha +\beta$=$\frac{-b}{a}$

9+(-5)=$\frac{-b}{a}$

   4=$\frac{-b}{a}$

 b=-4 and a=1

product of zeroes,

$\alpha$×$\beta$=$\frac{c}{a}$

9×(-5)=$\frac{c}{a}$

 -45=c   [since a=1]

so general form $ax^{2} +bx+c$

sub values of a b and c

so the polynomial is $x^{2} -4x-45$

PLEASE MARK ME AS BRAINLIEST