Math, asked by nath32555, 1 month ago

170/113/28 (1)
42. The compound interest on Rs. 24,000 compounded annually for 2 years at the
rate of 10% per annum is
(1) Rs. 5,000
(2) Rs. 5,020
(3) Rs. 5,040
(4) Rs. 5,060​

Answers

Answered by TheBrainliestUser
87

Answer:

  • (3) Rs 5,040 is the required answer.

Step-by-step explanation:

Given that:

  • The compound interest on Rs. 24,000 compounded annually for 2 years at the rate of 10% per annum.

To Find:

  • Compound interest.

Formula used:

In compound interest.

  • A = P(1 + R/100)ᵀ
  • C.I. = A - P

Where,

  • A = Amount
  • P = Principal
  • R = Rate of interest
  • T = Time
  • C.I. = Compound interest

We have:

  • Principal = Rs 24,000
  • Rate = 10% p.a.
  • Time = 2 years

Finding the amount:

⟶ A = 24000(1 + 10/100)²

⟶ A = 24000(1 + 0.1)²

⟶ A = 24000(1.1)²

⟶ A = 24000 × 1.1 × 1.1

⟶ A = 29040

∴ Amount = Rs 29,040

Finding the compound interest:

⟶ C.I. = 29040 - 24000

⟶ C.I. = 5040

∴ Compound interest = Rs 5,040

Answered by Anonymous
165

Answer:

Given :-

  • The compound interest on Rs 24000 compounded annually for 2 years at the rate of 10% per annum.

To Find :-

  • What is the compound interest or C.I.

Formula Used :-

\clubsuit Amount Formula :

 \longmapsto \sf\boxed{\bold{\pink{A =\: P\bigg(1 + \dfrac{r}{100}\bigg)^{n}}}}

where,

  • A = Amount
  • P = Principal
  • r = Rate of Interest
  • n = Time

\clubsuit Compound Interest or C.I Formula :

 \longmapsto \sf\boxed{\bold{\pink{C.I =\: Amount - Principal}}}\\

where,

  • C.I = Compound Interest

Solution :-

First, we have to find the amount :

Given :

  • Principal = Rs 24000
  • Rate of Interest = 10%
  • Time = 2 years

According to the question by using the formula we get,

 \implies \sf A =\: 24000\bigg(1 + \dfrac{1\cancel{0}}{10\cancel{0}}\bigg)^{2}\\

 \implies \sf A =\: 24000\bigg(1 + \dfrac{1}{10}\bigg)^{2}\\

 \implies \sf A =\: 24000\bigg(\dfrac{10 + 1}{10}\bigg)^{2}\\

 \implies \sf A =\: 24000\bigg(\dfrac{11}{10}\bigg)^{2}\\

 \implies \sf A =\: 240\cancel{0}\cancel{0} \times \dfrac{11}{1\cancel{0}} \times \dfrac{11}{1\cancel{0}}\\

 \implies \sf A =\: 240 \times 11 \times 11\\

 \implies \sf\bold{\purple{A =\: Rs\: 29040}}

Hence, the amount is Rs 29040 .

Now, we have to find the compound interest or C.I :

Given :

  • Amount = Rs 29040
  • Principal = Rs 24000

According to the question by using the formula we get,

 \implies \sf C.I =\: Rs(29040 - 24000)\\

 \implies \sf C.I =\: Rs\: 29040 - Rs\: 24000\\

 \implies \sf\bold{\red{C.I =\: Rs\: 5040}}

 \therefore The compound interest or C.I is Rs 5040 .

Hence, the correct options is option no (3) Rs 5040 .

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