Math, asked by sandhuashmeet1612, 6 months ago

170 students were asked whether they had read the ‘Bible’ (B), ‘The Lord of the Rings’ (L) or ‘War and Peace’ (W). 20 said they had read all three; 70 had read two but not all three; 35 had read none; 30 had read B and L but not W; 15 had read B and W not L; 60 had read W; 85 had read B. What is your probability that a randomly chosen student from his group has read The Lord of the Rings?

Answers

Answered by sonuvuce
0

The probability that a chosen student has read Lord of the Rings = 10/17

Step-by-step explanation:

Let the sets are

B : Students who have read Bible

L : Students who have read Lord of the Rings

W : Students who have read War and Peace

Total students

n(S) = 170

According to the question

n(B ∩ L ∩ W) = 20

n(B ∩ L) + n(L ∩ W) + n(W ∩ B) - 3n(B ∩ L ∩ W) = 70

or, n(B ∩ L) + n(L ∩ W) + n(W ∩ B) = 70 + 3×20 = 130

35 students have read none of the books

∴ n(B ∪ L ∪ W) = n(S) - 35 = 170 - 35 = 135

n(B ∩ L) = 30

n(W ∩ B) = 15

∴ n(L ∩ W) = 70 - 30 - 15 = 25

n(W) = 60

n(B) = 85

We know that

n(B ∪ L ∪ W) = n(B) + n(L) + n(W) - n(B ∩ L) - n(L ∩ W) - n(W ∩ B) + n(B ∩ L ∩ W)

or, 135 = 85 + n(L) + 60 - 130 + 20

or, n(L) = 135 - 35 = 100

Students who have read Lord of the Rings = 100

Probability that a chosen student has read Lord of the Rings

= 100/170 = 10/17

Hope this answer is helpful.

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