Question

1710 रुपए को तीन भागों में इस प्रकार बांटिए कि पहले भाग का 4 गुना,दूसरे भाग का 6 गुना और तीसरे भाग का 9 गुना परस्पर बराबर हो।​

Answer 1

amt will be distributed in the ratio 9:6:4

thus first part=9×1710/19 = 810

second part =6×1710/19 = 540

third part = 4×1710/19 = 360

Answer 2

The three parts are 810, 540 and 360 respectively.

Step-by-step explanation:

We need to divide 1710 in three parts such that 4 times of first part , 6 times of second part and 9 times of third part are equal.

$4x=6y=9z$

LCM of 4,6 and 9 is 36. Divide all sides by 36.

$\dfrac{4x}{36}=\dfrac{6y}{36}=\dfrac{9z}{36}$

$\dfrac{x}{9}=\dfrac{y}{6}=\dfrac{z}{4}$

It means the ratio of first second and third parts is 9:6:4.

Let first second and third parts are 9a,6a and 4a.

$9a+6a+4a=1710$

$19a=1710$

Divide both sides 19.

$a=90$

First part = 9a = 9(90) = 810

Second part = 6a = 6(90) = 540

Third part = 4a= 4(90) = 360

Therefore, the three parts are 810, 540 and 360 respectively.

#Learn more

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