Math, asked by rahulracer074, 1 year ago

=172.5m
Find the length of the side of a square (to two decimal places) whose area is equal to the
area of a rectangle of length 18.4 m and breadth 26 m.
Solution :​

Answers

Answered by bskkarur
4

Area of a rectangle = l×b

Area of a rectangle = l×b =18.4×26

Area of a rectangle = l×b =18.4×26 =478.4m^2

Area of a rectangle = l×b =18.4×26 =478.4m^2 Area of a square =a×a

Area of a rectangle = l×b =18.4×26 =478.4m^2 Area of a square =a×a = 478.4

Area of a rectangle = l×b =18.4×26 =478.4m^2 Area of a square =a×a = 478.4 a = √478.4

Area of a rectangle = l×b =18.4×26 =478.4m^2 Area of a square =a×a = 478.4 a = √478.4 = 21.8 m

Area of a rectangle = l×b =18.4×26 =478.4m^2 Area of a square =a×a = 478.4 a = √478.4 = 21.8 m The side of the square is 21.8m (approximately)

Area of a rectangle = l×b =18.4×26 =478.4m^2 Area of a square =a×a = 478.4 a = √478.4 = 21.8 m The side of the square is 21.8m (approximately)

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