Question

175 litres of a solution contains 88% of acid and
the rest water. How many litres of water must be
added such that the resulting mixture contains
23% of water?

Answer 1

Step-by-step explanation:

175 litres of a solution contains 88% of acid and (100-88)% of water. Water present= 12/100 ×175=21 litres and Acid present= 154 litres. The amount of water in litres that should be added =>x litres such that the resulting mixture has 23% of water. So

$\frac{21 + x}{175 + x} = \frac{23}{100} = > 2100 + 100x = 23x +$

$23 \times 175 = > 100x - 23x = 4075 -$

$2100 = > 77x = 1975 = > x = \frac{1975}{77}$

=>x=25. 25 litres must be added such that the resulting mixture has 23% of water. Hope it helps you.