Chemistry, asked by VarshaDarivemula, 7 months ago

177
77. Relative humidity of air is 80%
at 27°. If the aqueous tension at
the same temperature is 27 mm
Hg, partial pressure of water
vapour in the air will be
1) 27 mm Hg 2) 25 mm Hg
3) 23 mm Hg 4) 21.60 mm Hg​

Answers

Answered by abeerfatima387
1

Answer:

4 will be the answer . .......

Answered by sairammaruri
0

Answer:

Explanation:

% relative humidity = partial pressure of water ×(  

aqueoustension

100

​  

)

⟹80= partial pressure of water ×(  

27

100

​  

)

Hence, the partial pressure of water is 21.6 mm.

Hence, the correct answer is option D.

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