Question

(179
173) A committee of 7 members is to be choosen
from 6 chartered accountants, 4 economists
and 5 cost accountants. The number of ways
that atleast one from economists, cost
accountants and atleast 3 from CA's
a) 3760 3570 C)3770 d) 3650​

Answer 1

Answer:

Atleast 1 frm each and atleast 3 4m Chtd Accnt.

given

6 Chtd Accnt

4 Ecnmst

5 Cost Accnt

possible combinations are

(i) 3 Chtd Accnt + 1 Ecnmst + 2 Cost Accnt==>6c3 * 4c1 * 5c2=800

(ii) 3 Chtd Accnt + 2 Ecnmst + 1 Cost Accnt==>6c3 * 4c2 * 5c1=600

(iii) 4 Chtd Accnt + 1 Ecnmst + 1 Cost Accnt==>6c4* 4c1 * 5c1=300

Step-by-step explanation:

Atleast 1 frm each and atleast 3 4m Chtd Accnt.

given

6 Chtd Accnt

4 Ecnmst

5 Cost Accnt

possible combinations are

(i) 3 Chtd Accnt + 1 Ecnmst + 2 Cost Accnt==>6c3 * 4c1 * 5c2=800

(ii) 3 Chtd Accnt + 2 Ecnmst + 1 Cost Accnt==>6c3 * 4c2 * 5c1=600

(iii) 4 Chtd Accnt + 1 Ecnmst + 1 Cost Accnt==>6c4* 4c1 * 5c1=300

total==>800+600+300 ==1700

correct me if im wrong...

Answer 2

Step-by-step explanation:

179

173) A committee of 7 members is to be choosen

from 6 chartered accountants, 4 economists

and 5 cost accountants. The number of ways

that atleast one from economists, cost

accountants and atleast 3 from CA's

a) 3760 3570 C)3770 d) 3650