Question

17abc-34ab^2
factorisation using algebraic expressions

Answer 1

Answer:

The given factors can be written in expanded form as,

17abc = 17 × a × b × c.

34ab2 = 2 × 17 × a × b × b.

51a2b = 3 × 17 × a × a × b.

So, common factors in the above is 17 × a × b.

= 17ab.

Answer 2

Answer:

17abc=17×a×b×c

34ab²=17×2×a×b×2

common factor are 17,a,b

Step-by-step explanation:

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