Question

17g of agno3 is treated with 25g of hcl.find the mass of agcl formed.Agno3+ hcl ->Agcl+Hno3​

Answer 1

Answer:

16.99g

Explanation:

no of mol of AgNO3 = 17g/169.9g/mol= 0.1 mol

no.of mol of HCl = 25g/36.5g/mol= 0.684mol

AgNO3 is the limiting reactant.

no.of moles of AgCl formed = 0.1mol=

(0.1mol)×(169.9g/mol)

= 16.99g