17th one. Please do it as soon as possible.
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the points are A(-2,1) B(a,b) C(4,1)
and are collinear ...
then area of triangle made from these points will be zero ..
then [-2(b-1) + a(1-1) + 4(1-b)]=0
-2b+2+4-4b=0
-6b=-2
b=1/3
and a = 1 +b
then a = 4/3
I hope this will be helpful to you
and are collinear ...
then area of triangle made from these points will be zero ..
then [-2(b-1) + a(1-1) + 4(1-b)]=0
-2b+2+4-4b=0
-6b=-2
b=1/3
and a = 1 +b
then a = 4/3
I hope this will be helpful to you
brainlyuser39:
thxx
where
it is incorrect
please inform
me
it is correct
and i have left 1/2 in starting
hello
reply
-2b+2+4-4b
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