Question

-17x²(3x - 4)
plz explain
step by step​

Answer 1

Answer:

= -51x^3+68x^2

this is the answer

it may be helpful

Answer 2

I think your question is incomplete

I guess the question is find weather $-17x^{2} (3x - 4) = 0$ is a quadratic or not

               here I'm giving answer for the above question

Step-by-step explanation:

$-17x^{2} (3x - 4) = 0$

on simplifying we get

$-51x^3 + 68x^2$

this equation is not quadratic

as the degree of the variable is more than 3 and this equation cannot be written in the form of $ax^{2} + bx + c = 0$

therefore, $-17x^{2} (3x - 4) = 0$ is not a quadratic

hope this was helpful

$thankyou$