18.0 gof magnesium is added to 200 mL of 2.00 M HCl. The mass, in gram, of magnesium that is left behind after the reaction is complete is (Molar mass of Mg=24) (A) 4.2 (B) 8.4 (C) 13.2 (D) 15.6
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Answer:
(c)13.2g
Explanation:
concept: molarity =moles of solute / volume of solution
Then find no. of moles of Mg reacted,then left behind mass of Mg
given: molarity of HCl=2.00M
volume=200ml
weight of Mg is added=18g
molar mass of Mg=24
To find:
mass of Mg left behind after reaction is completed
explanation:molarity =moles of solute / volume of solution
2.00=moles of solute/200
2.00*200=moles of solute
400mols =moles of solute
no. of moles of Mg reacted=200mols
200/1000*24=4.8g
Mg moles left behind =18-4.8g
final answer:13.2g
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