Question

(-18) 1's complement ​

Answer 1

Let's find the binary equivalent of $\displaystyle\sf {(18)_{10}.}$

$\begin {tabular}{r|lr}2&18&\\\cline{2-2}2&9&0\\\cline {2-2}2&4&1\\\cline {2-2}2&2&0\\\cline {2-2}&1&0\\\cline {2-2}\end {tabular}$

Hence the binary equivalent is,

$\displaystyle\longrightarrow\sf {(18)_{10}=(10010)_2}$

Making it as 8 - bit,

$\displaystyle\longrightarrow\sf {(18)_{10}=(00010010)_2}$

Therefore,

$\displaystyle\longrightarrow\sf {\underline {\underline {(-18)_{10}=(11101101)_2}}}$