Question

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3. If the area of a semicircle is 308 cm2, find the length of its diameter.
4. The area of a trapezium is 96 cm2. If the lengths of its two parallel sides are 14 cm and
10 cm, then find the perpendicular distance between parallel sides.
The marka ohtninad hwn abdul​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

3.Therefore the Diameter of the circle is=28 cm.

4.Therefore the perpendicular distance between the parallel sides is 8 cm.

Step-by-step explanation:

3.

Given the area of a semicircle is 308 cm²

The area of circle is $\pi r^2$

Let the radius of the semicircle be r.

Then the area of a semicircle is $\frac{\pi r^2}{2}$. [since semicircle is a half of circle]

According to the problem,

$\frac{\pi r^2}{2}=308$

$\Rightarrow r^2=\frac{308\times2}{\pi}$

$\Rightarrow r^2 = 196$

$\Rightarrow r=\sqrt{196}$

$\Rightarrow r=14$

Therefore the radius of the circle is = 14 cm

Diameter= radius × 2

Therefore the Diameter of the circle is=(14×2) cm=28 cm

4.

Given, the area of a trapezium is 96 cm².The length of its parallel sides are 14 cm and 10 cm.

Let the perpendicular distance between the parallel sides be x.

Area of a trapezium is $=\frac{1}{2}\times \textrm{(sum of parallel sides)}\times\textrm{(distance between the parallel sides)}$

$=[\frac{1}{2} \times (14+10)\times h]$ cm²

According to the problem,

$[\frac{1}{2} \times (14+10)\times h]=96$

$\Rightarrow h=\frac{96 \times 2}{14+10}$

$\Rightarrow h=\frac{96 \times 2}{24}$

$\Rightarrow h=8$

Therefore the perpendicular distance between the parallel sides is 8 cm.