Question

18 + 2x square + 12x = 0​

Answer 1

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$18 + 2x {}^{2} + 12x = 0 \\ 2x {}^{2} + 12x = 0 - 18 \\ 4x {}^{} + 12x = - 18 \\ 16x = - 18 \\ x = \frac{ - 18}{16} = \frac{ - 9}{8}$

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Answer 2

Answer:

2x² + 12x +18 = 0

2x²+ 6x + 6x + 18 = 0

2x(x+3) +6(x+3) = 0

(x + 3) (2x + 6) = 0

x = -3. or x = -3