Question

18-3/4y=11+y
please answer fast​

Answer 1

Answer:

1

Step-by-step explanation:

18-3-11=y*4y

4=4y squared

4/4=y squared

1=y squared

square root of 1= 1

the square root of y squared=y

therefore y =1

Answer 2

$\large\underline\bold{ANSWER \huge{\checkmark}}$

$\dashrightarrow 18-\dfrac{3}{4y}= 11+y$

$\implies 18-11=y+\dfrac{3}{4y}$

$\implies 7= \dfrac{4y^2+3}{4y}$

$\implies 7\times 4y=4y^2+3$

$\implies 28y-4y^2-3=0$

$\implies -4y^2+28y-3=0$

$\therefore solving\:by\:quadratic\:formula,$

$\dashrightarrow a=-4\\ b=28\\c=-3$

$\therefore y= \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\dashrightarrow y= \dfrac{-(28)\pm\sqrt{(28)^2-4(-4)(-3)}}{2(-4)}$

$\implies y= \dfrac{-28\pm \sqrt{(784)-48}}{-8}$

$\implies y= \dfrac{-28\pm\sqrt{736}}{-8}$

$\implies y= \dfrac{-28\pm (27.12)}{-8}$

$\implies y= \dfrac{-28+27.12}{-8} , \dfrac{-28-27.12}{-8}$

$\implies y= \dfrac{0.88}{8}, \dfrac{55.12}{8}$

$\implies y= 0.11 , 6.89$

or

$\dashrightarrow y= \dfrac{7}{2}-\dfrac{1}{2}\sqrt{46}\:, \dfrac{7}{2}+\dfrac{1}{2}\sqrt{46}$

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