Question

18-3p-11q+5pq-pq
18 - 3p - 11q + 5pq - 2p { q}^{2} + 5 {p}^{2} q - 4 {q}^{2}q - 3pq + 5p {q}^{2} - 8p + 7q - 2018−3p−11q+5pq−2pq
2
+5p
2
q−4q
2
q−3pq+5pq
2
−8p+7q−20​

Answer 1

Answer:

$Subtracting 4p2q−3pq+5pq2−8p+7q−10 from 18−3p−11q+5pq−2pq2+5p2q, we have</p><p>= (18−3p−11q+5pq−2pq2+5p2q)−(4p2q−3pq+5pq2−8p+7q−10) </p><p>= 18−3p−11q+5pq−2pq2+5p2q−7p2q+3pq−5pq2+8p−7q+10 </p><p>= 28+5p−78q+8pq−7pq2+p2q</p><p></p><p></p><p>$

Answer 2

Answer:

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