Question

18. A 300 pF capacitor is
charged by a 100 V supply. It
is then disconnected and
connected to another
uncharged 600 pF capacitor.
The amount of electrostatic
energy (in micro joules) lost
in the process is​

Answer 1

Answer:

Capacitance of the capacitor, C = 600 pF

Potential difference, V = 200 V

Electrostatic energy stored in the capacitor is given by,

If supply is disconnected from the capacitor and another capacitor of capacitance C = 600 pF is connected to it, then equivalent capacitance (C') of the combination is given by,

New electrostatic energy can be calculated as

Loss in electrostatic enegy = E - E'

                                       = 1.2 x 10-5  -  0.6 x 10-5

                                       = 0.6 x 10-5

                                       = 6 x 10-6 J  

Therefore, the electrostatic energy lost in the process is 6 x 10-6 J.  

Explanation: