Question

18. A bag contains 5red balls ,7 green balls and 9 white balls. A ball is drawn out random
.What is the probability that the drawn out ball be
a) Green ball
b) white ball
c) no red ball​

Answer 1

Answer:

3 white balls are in the faviour of event while 4 black balls are not in the faviour. Probability = favioural cases of event / total cases. Here event is drawing the ball from bag. Favioural cases of event will be 3.

Step-by-step explanation:

i have answered as other that your self you can try understand and

Answer 2

Answer:

p(E) green balls = 7/21 = 1/3

p(E) white balls =9/21 =3/7

p(E) not a red ball =green +white /21

=16/21

explanation :

you r better aware of Formula

p(E)= no of favorable outcomes /total no of possible outcomes