Question

18. A bicycle moves with a constant velocity of 5 km/h
for 10 minutes and then decelerates at the rate
1 km/h, till it stops. Find the total distance covered
by the bicycle.
24​

Answer 1

velocity of bicycle (u) = 5 km / hr

time taken (t) = 10 minutes

=10/60 hr = 1/6 hr

deceleration ( use negative sign) = -1 km /hr^2

as we know , speed formula

let the initial distance covered = d1

d1 = u*t. (distance[d]=speed[u]*time[t]

5*1/6

5/6 km = d1

let the final distance covered be d2 , final velocity will become (v)

acc. to question :

by formula

v^2 - u^2 = 2as

we have v = 0 ( as it have to be stopped given)

putting values

(0)^2 - (5)^2 = 2*-1 * d2. as s = d2

25 = -2 * d2

d2 = 25/ -2 km

total distance = d1 + d2

Answer 2

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