18. A block of mass 120 g moves with a speed of 6.0 m/s
on a frictionless horizontal surface towards another
block of mass 180 g kept at rest. They collide and the
first block stops. Find the speed of the other block
after the collision.
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m1 = 120 g = 0.12kg , u1 = 6 m/s
m2= 180g = 0.18kg , u2 = 0
v1 = 0 and v2= ?
according to conservation of momentum
m1u1 + m2u2 = m1v1 + m2v2
0.12×6 + 0 = 0 + 0.18×v2
0.72 = 0.18 × v2
v2 = 4m/s
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