18. A candle of radius 1 cm is floating in a liquid in a
cylindrical container of radius 1 m. If the candle is
burning at the rate of 1.5 cm/h, then the top of the
candle will in the given figure)
(1) Fall at the rate of 1.5 cm/h
(2) Remain at the same height
(3) Fall at the rate of 3 cm/h
(4) Fall at the rate of 0.75 cm/h
Answers
Answered by
30
Answer:4
Explanation:
Equate the weight instantaneous equal to buoyant force.
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Answered by
40
Answer:
It falls at the rate of 0.75 cm/h.
(4) is correct option.
Explanation:
Given that,
Radius of candle = 1 cm
Radius of cylinder container = 1 m
Rate of burning = 1.5 cm/h
According to Archimedes' principle
Weight of candle is equal to weight of liquid displaced.
We need to calculate the volume of candle
put the value into the formula
Weight of candle = weight of liquid displaced
Put the value into the formula
The length of candle after one hour
We need to calculate the burning rate
Using formula of burning rate
Put the value into the formula
In one hour candle melts 0.75 cm.
Hence, It falls at the rate of 0.75 cm/h.
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