Question

18. A car is moving with a speed of 10m/s on a circular track. If co-efficient of friction be 0.5 then the radius of
turning of the car will be:
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Answer 1

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$μ = 0.5$

$g = 10 \: ms {}^{ - 2}$

$V= 10 \: ms {}^{ - 1}$

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$Vmax = \sqrt{μrg }$

$10 = \sqrt{0.5 \times r \times 10}$

$(10) {}^{2} = 5r$

$5r = 10 \times 10$

$r = \frac{10 \times 10}{5}$

$r = 2 \times 10$

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