Question

18) A cricketer can throw a ball to a maximum HR of 100m. How much high above the ground can
he throw the same ball ?​

Answer 1

Answer:

The formula for range is given as

Range = u^2 sin 2© / g

Max range = u^2/g when the value of sin 2© = 1 or © = π/4

So,

u^2/g = 100 this is given.

Now, max height = u^2 sin^2 © / 2g = (u^2/g) * ( sin^2 © / 2)

= 100*( sin^2 π/4)/2 = 25 metres

Answer 2

Answer:

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