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In ABC if a,b,c are in A.P. then find the value of tan a/2 tanc/2
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Since a,b,c are in A.P 2b=a+c
We know the half-angle formula
tan2A=s(s−a)(s−b)(s−c), tan2C=s(s−c)(s−a)(s−b)
Now,tan2Atan2C=s(s−a)(s−b)(s−c)s(s−c)(s−a)(s−b)
=s(s−b) on simplification
Multiply both sides by 2 we get
=2s(2s−2b)
=a+b+c(a+b+c−2b) where 2s=a+b+c
=a+b<
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