Question

18. A magnet of length 10cm and pole strength
0.5Am is placed normal to a uniform magnetic field
of strength 5 x 10 weber m. The moment of the
couple acting on it is​

Answer 1

Answer:axis

Explanation:

Answer 2

Answer:2.5×10^-6

Explanation:d=10cm=10×10^-2m

m^2=F.d

=B.m^2.d

=5×10^-5×0.5×10×10^-2

=2.5×10^-6 N-m